統計検定準1級例題集解答/解答例と解説

選択問題及び部分記述問題問1

問題の要約

\begin{aligned} P (A) = 0.45 \\ P (B) = 0.45 \\ P (C) = 0.4 \\ P (A \cap B) = 0.2 \\ P (B \cap C) = 0.1 \\ P (C \cap A) = 0.15 \\ P (A \cap B \cap C) = 0.05 \end{aligned}

$\begin{align} & P(A) = 0.45 \\ & P(B) = 0.45 \\ & P(C) = 0.4 \\ & P(A \cap B) = 0.2 \\ & P(B \cap C) = 0.1 \\ & P(C \cap A) = 0.15 \\ & P(A \cap B \cap C) = 0.05 \end{align}$

$P(A \cup B)$ を求めよ．
$P(A \cup B \cup C)$ を求めよ．

解答

答 : ③

$\begin{aligned} P (A \cup B) & = P (A) + P (B) - P (A \cap B) \\ = 0.45 + 0.45 - 0.2 = 0.7 \end{aligned}$
$\begin{align} P(A \cup B) &= P(A) + P(B) - P(A \cap B) \\ &= 0.45 + 0.45 - 0.2 = 0.7 \end{align}$
答 : ③

$\begin{aligned} P (A \cup B \cup C) & = P (A) + P (B) + P (C) - P (A \cap B) - P (B \cap C) - P (C \cap A) + P (A \cap B \cap C) \\ = 0.45 + 0.45 + 0.4 - 0.2 - 0.1 - 0.15 + 0.05 \\ = 0.9 \end{aligned}$
$\begin{align} P(A \cup B \cup C) &= P(A) + P(B) + P(C) - P(A \cap B) - P(B \cap C) - P(C \cap A) + P(A \cap B \cap C) \\ &= 0.45 + 0.45 + 0.4 - 0.2 - 0.1 - 0.15 + 0.05 \\ &= 0.9 \end{align}$

統計検定 準1級 例題集 解答/解答例と解説

選択問題及び部分記述問題 問1

問題の要約

解答

統計検定準1級例題集解答/解答例と解説

選択問題及び部分記述問題問1